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22320 cal heat is supplied to 100g of ice at 0°C. If the latent heat of fusion of ice is 80cal g–1 and latent heat of vaporization of water is 540 cal g–1, the final amount of water thus obtained and its temperature respectively are A. 8g, 100°C B. 100g, 90°C C. 92g, 100°C D. 82g, 100°C

22320 cal heat is supplied to 100g of ice at 0°C. If the latent heat of fusion of ice is 80cal g–1 and
latent heat of vaporization of water is 540 cal g–1, the final amount of water thus obtained and its
temperature respectively are
A. 8g, 100°C B. 100g, 90°C C. 92g, 100°C D. 82g, 100°C

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1 Answers

Vikas TU
14149 Points
2 years ago
 
Answer would be option C
The ice would take 8000cal to turn into water by formula   mass×80
Then the water would take 10000 cal   by formula mass× c × change in temp(which is 100) 
So remaining 4320cal would turn 8g of water into vapour

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