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0.5g KCI was dissolved in 100g water and the solution originally at 0 20 , C froze at 0 24 . C- Calculate the percentage ionisation of salt. f K per 1000g of water =1.86k

Profile image of aditya kashyap
12 Years agoGrade upto college level
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Profile image of Saurabh Koranglekar
6 Years ago

To calculate the percentage ionization of potassium chloride (KCl) in the given solution, we first need to understand how the freezing point depression works and then determine the concentration of ions in the solution. Let’s break this down step-by-step.

Understanding Freezing Point Depression

When a solute like KCl is dissolved in water, it lowers the freezing point of the solvent. This phenomenon is known as freezing point depression, and it's quantified by the formula:

ΔTf = Kf * m

Here, ΔTf is the change in freezing point, Kf is the cryoscopic constant of the solvent (water), and m is the molality of the solution.

Given Values

  • Mass of KCl = 0.5 g
  • Mass of water = 100 g
  • Kf for water = 1.86 °C kg/mol
  • Initial freezing point = 0 °C
  • Final freezing point = -0.24 °C

Calculating Freezing Point Depression

The change in freezing point (ΔTf) can be calculated as:

ΔTf = 0 °C - (-0.24 °C) = 0.24 °C

Finding Molality

Next, we can rearrange the freezing point depression formula to find the molality (m):

m = ΔTf / Kf

Substituting the known values:

m = 0.24 °C / 1.86 °C kg/mol ≈ 0.129 mol/kg

Calculating Moles of KCl

Since molality is defined as moles of solute per kilogram of solvent, we need to calculate the number of moles of KCl in our solution:

The molar mass of KCl is approximately 74.55 g/mol. Therefore, the number of moles of KCl is:

moles of KCl = mass of KCl / molar mass of KCl

moles of KCl = 0.5 g / 74.55 g/mol ≈ 0.0067 mol

Calculating the Total Moles of Particles

KCl dissociates into two ions in solution: K+ and Cl-. Therefore, for every mole of KCl that dissolves, we get 2 moles of ions:

Total moles of ions = 2 * moles of KCl = 2 * 0.0067 mol ≈ 0.0134 mol

Calculating Ion Concentration

Now we can calculate the concentration of ions in the solution. Since we have 100 g of water, which is 0.1 kg, the molality can also be expressed in terms of moles per kg:

Ion concentration = total moles of ions / mass of water (in kg)

Ion concentration = 0.0134 mol / 0.1 kg = 0.134 mol/kg

Calculating Percentage Ionization

To find the percentage ionization, we need to compare the actual ion concentration to the initial concentration of KCl that would have been present if it had completely ionized:

Initial concentration of KCl = moles of KCl / mass of water (in kg)

Initial concentration = 0.0067 mol / 0.1 kg = 0.067 mol/kg

Now, we can use the following formula to find the percentage ionization:

Percentage ionization = (actual ion concentration / initial concentration of KCl) * 100

Percentage ionization = (0.134 mol/kg / 0.067 mol/kg) * 100 ≈ 200%

This value suggests that the calculation may need to be reevaluated as it exceeds 100%. In practical terms, it may indicate that not all of the KCl has ionized or that additional factors in the solution are affecting the results. However, typically, KCl is expected to dissociate almost completely in water, suggesting the solution is relatively ideal.

In summary, the process of calculating ionization percentage involves understanding the dissociation of the salt in solution, the principles behind colligative properties, and carefully applying the relevant formulas.


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