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Grade: 11
        What is the magnitude of a point charge chosen so that the electric field 50 cm away has magnitude 2N/C ?
8 months ago

Answers : (1)

Arun
13919 Points
							
k = 9 * 10 ^ 9 
r = 0.5 m 
E = K q/r^2 = 2 N/c 
q = E * r ^ 2 / k 
= 2 * 0.25 / 9* 10^9 C
 = 0.5 * 10^-9 /9
= 5.5 * 10^-11 c
8 months ago
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