what is the electric field due to the nucleus at the first bohr orbit

The charge at nucleus is q = 1.6x10^-19 C
The distance of first orbit from nucleus is r = 53 picometer = 53x10^-12 m
The electric field due to nucleus at the first orbit E = (1/4pie epsilon not)x(q/r²)
E = 9x10⁹ x[1.6x10^-19 /(53x10^-12)²]
on calculating E = 2.72x10¹³ N/ m²
Thanks & Regards,
Nirmal Singh
Askiitians Faculty

The Charge of the Nucleus q = 1.6x10^-19 C
The distance of first orbit from the Nucleus r = 53 picometer = 53x10^-12
The electric field form the nucleus at first bohr orbit is E = (1/4pie epsilon not)*q/ r^2
E = (9x10^9)x[1.6x10^-19/(53x10^-12)^2]
On calculating E = 2.72x1013 N/m^2
Thanks & Regards,
Nirmal Singh
Askiitians Faculty