Two points P and Q are maintained at a potential of 10V and -4V respectively.The work done in moving 100 electrons from P to Q is?

Dear Student,
Please find below the solution to your problem.

Work done = q*(change in potential at those 2 points).
= 1.602 x 10^-19 * ( 10 – -4)
= 1.602 x 10^-19 x 14 Joule.
this is for one electron, As work is the scalar quantity,
Total work done = 1.602 x 10^-19 x 14 x 100 Joule.
= 224.28 x 10^-18 Joule

Thanks and Regards