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Two points P and Q are maintained at a potential of 10V and -4V respectively.The work done in moving 100 electrons from P to Q is?
Work done = q*(change in potential at those 2 points). = 1.602 x 10^-19 * ( 10 – -4) = 1.602 x 10^-19 x 14 Joule. this is for one electron, As work is the scalar quantity,Total work done = 1.602 x 10^-19 x 14 x 100 Joule. = 224.28 x 10^-18 Joule.
Dear Student,Please find below the solution to your problem.Work done = q*(change in potential at those 2 points). = 1.602 x 10^-19 * ( 10 – -4) = 1.602 x 10^-19 x 14 Joule.this is for one electron, As work is the scalar quantity,Total work done = 1.602 x 10^-19 x 14 x 100 Joule. = 224.28 x 10^-18 JouleThanks and Regards
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