Two points P and Q are maintained at a potential of 10V and -4V respectively.The work done in moving 100 electrons from P to Q is?

Question

Vikas TU · Answer

Work done = q*(change in potential at those 2 points). = 1.602 x 10^-19 * ( 10 – -4) = 1.602 x 10^-19 x 14 Joule. this is for one electron, As work is the scalar quantity, Total work done = 1.602 x 10^-19 x 14 x 100 Joule. = 224.28 x 10^-18 Joule.

Rishi Sharma · Answer

Dear Student,
Please find below the solution to your problem.

Work done = q*(change in potential at those 2 points).
= 1.602 x 10^-19 * ( 10 – -4)
= 1.602 x 10^-19 x 14 Joule.
this is for one electron, As work is the scalar quantity,
Total work done = 1.602 x 10^-19 x 14 x 100 Joule.
= 224.28 x 10^-18 Joule

Thanks and Regards

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Two points P and Q are maintained at a potential of 10V and -4V respectively.The work done in moving 100 electrons from P to Q is?

Two points P and Q are maintained at a potential of 10V and -4V respectively.The work done in moving 100 electrons from P to Q is?

2 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Electrostatics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship