Two identical spheres A and B are equally charged and seperated by a certain distance. Another identical uncharged sphere C is brought in contact with A and then placed mid way between A and B,. Calculate the resultant force on C if initial force between A and B is 2*10^-5 N.

Question

Eshan · Answer

Let the distance between the charges be $r$ and their charges be $q$ each.

Hence the force between them is $\dfrac{kq^2}{r^2}=2\times 10^{-5}N$

When identical uncharged sphere is brought in contact, the charge on the charged sphere gets divided equally. Hence charge on both A and C becomes $\dfrac{q}{2}$ .
Hence force on C due to A after it is moved to the mid point= $\dfrac{k(\dfrac{q}{2})(\dfrac{q}{2})}{(\dfrac{r}{2})^2}=\dfrac{kq^2}{r^2}=F$

Force on C due to B= $\dfrac{kq(\dfrac{q}{2})}{(\dfrac{r}{2})^2}=\dfrac{2kq^2}{r^2}=2F$
Hence net force on C=2F-F=F

Gitanjali Rout · Answer

Hence net force on C=2F-F=F Force on C due to B= .Hence force on C due to A after it is moved to the mid point= When identical uncharged sphere is brought in contact, the charge on the charged sphere gets divided equally. Hence charge on both A and C becomes each.Hence the force between them is and their charges be Let the distance between the charges be thanks

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Two identical spheres A and B are equally charged and seperated by a certain distance. Another identical uncharged sphere C is brought in contact with A and then placed mid way between A and B,. Calculate the resultant force on C if initial force between A and B is 2*10^-5 N.

Two identical spheres A and B are equally charged and seperated by a certain distance. Another identical uncharged sphere C is brought in contact with A and then placed mid way between A and B,. Calculate the resultant force on C if initial force between A and B is 2*10^-5 N.

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