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Two identical spheres A and B are equally charged and seperated by a certain distance. Another identical uncharged sphere C is brought in contact with A and then placed mid way between A and B,. Calculate the resultant force on C if initial force between A and B is 2*10^-5 N.
Two identical spheres A and B are equally charged and seperated by a certain distance. Another identical uncharged sphere C is brought in contact with A and then placed mid way between A and B,. Calculate the resultant force on C if initial force between A and B is 2*10^-5 N.


3 years ago

Eshan
2095 Points
							Let the distance between the charges beand their charges beeach.Hence the force between them isWhen identical uncharged sphere is brought in contact, the charge on the charged sphere gets divided equally. Hence charge on both A and C becomes.Hence force on C due to A after it is moved to the mid point=Force on C due to B=Hence net force on C=2F-F=F

2 years ago
Gitanjali Rout
184 Points
							Hence net force on C=2F-F=FForce on C due to B=.Hence force on C due to A after it is moved to the mid point=When identical uncharged sphere is brought in contact, the charge on the charged sphere gets divided equally. Hence charge on both A and C becomeseach.Hence the force between them isand their charges beLet the distance between the charges bethanks

2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions