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Two identical metal spheres passes +60c and -20c of charges. They are brought in contact and then separated by 10cm and the force between them is

HARSHITH , 7 Years ago
Grade 12
anser 1 Answers
Praveen Kumar

Last Activity: 7 Years ago

Charge +60 C and charge - 20 C on the two spheres. 
Total charge in the system Q = 60-20 = 40 C
 
Since the two spheres are identical so they will share equal charges after seperated from contact.
So each shpere will have acharge of 20 C on it.
Now the seperation is
r=10 cm = 0.1 m and
q1 = 20 C 
q2 = 20 C
 
Now the electrostatics force will be
 
F = \frac{k*q1*q2}{r^{2}}
  F = \frac{9*10^{9}*20*20}{0.1^{2}}
F = 3.6*10^{14} N
                               

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