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Two identical balls A&B are moving with same velocity.If velocity of A is reduced to half and half and of `B` to zero then the rise in temperatures of A to that of `B` is

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3 years ago

Arun
24742 Points
```							Let m be the mass and v be the initial velocity of the balls. Let s be their specific heat capacity.Energy dissipated for ball A = = Initial KE - Final KE= 1/2 mv^2 - 1/2 m (v/2)^2= 3/8 mv^2 Now m*s* $\Delta$tA= 3/8 mv^2Hence$\Delta$ tA = 3 v^2/ 8s Energy dissipated for ball B = = Initial KE - Final KE= 1/2 mv^2 - 0= 1/2 mv^2 Now m*s* $\Delta$ tB = 1/2 mv^2Hence $\Delta$tB= v^2/ 2s Hence$\Delta$tA/$\Delta$tB = 3/4
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3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions