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Grade: 12
        
 
Two charges of value 2micro c and negative 5o micro c are placed at adistance 80 cm apart. calculate the distance point from the smaller charge where the field intensity will be zero
 
 
 
 
one year ago

Answers : (1)

Arun
15903 Points
							
Dear Priya
 
Let the diatance from smaller charge = x
Hence
K* 2 /x² + K* -50/(80+x)² = 0
(80+x)²/x² = 25 = 5²
80+x = 5x
4x = 80
x = 20 cm
 
Regards
Arun (askIITians forum expert)
11 months ago
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