Two charges equal in magnitude and opposite in polarity are placed at certain distance apart and force acting between them is F. If 75 % charge of one is transferred to another, then the force between charges becomes
Prabhmeet
9 Years agoGrade 12
1 Answer
Khimraj
9 Years ago
Just write the expression and then compareF= Kq(-q)/r²Now q` = 1/4qAnd -q`= -1/4qF` = k(q/4)(-q/4)/r²F` = F/16
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