Grade 12Mechanics

Three identical particles placed on corner of equilateral triangle having mass m and charge Q .if we release them simultaneously then find maximum speed of any one particle

Shiv

9 Years agoGrade 12

1 Answer

Amogh Dasture

9 Years ago

The total potential energy of the three particle system will be converted into kinetic energy at infinity which be equally divided among the three particles.

So,

Total PE= $\frac{3kQ^2}{r}$ (As there are three particles)

This will be converted into total kinetic energy at infinity. Let energy of 1 particle at infinity be E

$\therefore E=\frac{KE}{3}=\frac{3kQ^2}{3r}=\frac{kQ^2}{r}$

Now,

$\frac{1}{2}mv^2=\frac{kQ^2}{r}$

$\therefore v=Q \sqrt{\frac{2mk}{r}}$

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Three identical particles placed on corner of equilateral triangle having mass m and charge Q .if we release them simultaneously then find maximum speed of any one particle

Shiv

1 Answer

Amogh Dasture

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