# There were 2 other options too..involving squares of option A & B..which I think.. is not d answer..

Arun
25758 Points
4 years ago
Dear student

Potential is given by

$-\int_{0}^{x} E. dx$
Hence

$V =-E.x$

This is the potential at positive x- axis.
Yes you have to consider the negative sign.
Option B is correct.
Rohit
103 Points
4 years ago
Clearly E= - V/d.
Now V is - Ed.
Here d is x .
Hence V= - Ex.
See they have not asked magnitude but the value.