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There were 2 other options too..involving squares of option A & B..which I think.. is not d answer..

Apeksha Bhaskar Vyas , 6 Years ago
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anser 2 Answers
Arun

Last Activity: 6 Years ago

Dear student
 
Potential is given by
 
-\int_{0}^{x} E. dx
Hence
 
V =-E.x
 
This is the potential at positive x- axis.
Yes you have to consider the negative sign.
Option B is correct.

Rohit

Last Activity: 6 Years ago

Clearly E= - V/d.
Now V is - Ed.
Here d is x .
Hence V= - Ex.
See they have not asked magnitude but the value.
If magnitude was asked the answer would be option a).
Hope it clears it doubt.
Regards.
Rohit.

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