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The intensity of electric field, due to a uniformly charged infinite cylinder of radius R, at a distance r(>R) from its axis is proportional to

The intensity of electric field, due to a uniformly charged infinite cylinder of radius R, at a distance r(>R) from its axis is proportional to

Grade:12

1 Answers

Piyush Kumar Behera
436 Points
4 years ago
The electric field of an infinite cylinder of uniform volume charge density can be obtained by a using Gauss` law. Considering a Gaussian surface in the form of a cylinder at radius r > R, the electric field has the same magnitude at every point of the cylinder and is directed outward. The electric flux is then just the electric field times the area of the cylinder.
Hence the Electric Field is inversely proportional to ror proportional to \frac{1}{r}I hope it helps!!RegardsPiyush Kumar Behera.

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