MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
the flux of the E=3i+24j+6k through a portion of 5m^2 of the plane the normal to which is 2i+4j+6k
3 months ago

Answers : (1)

Arun
22796 Points
							
 
Dear student 
E = 3i + 24j + 6k 
So, area vector magnitude = 5 
and it is normal to 2i+ 4j +6k
area vector = 5k 
Flux = E.dA 
Flux = (3i+24j+6k ). 5k 
=> 30k 
 
Regards
Arun
3 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details