Flag Electrostatics> The figure below shows a cross section th...
question mark

The figure below shows a cross section through a very large nonconducting slab ofthickness d=9.40 mm and uniform volume charge density p=5.80 fC/m3. The originof an x axis is at the slab’s centre. What is the magnitude of the slab’s electric fieldat an x coordinate of (a) 0, (b) 2.00 mm, (c) 4.70mm, (d) 26 mm?

Shubham Rai , 7 Years ago
Grade 12th pass
anser 1 Answers
Vikas TU

Last Activity: 7 Years ago

Volume charge density = 5.80 fC/m3
Thickness d = 9.40 mm
At 0, Electric field will be zero.
At 2 mm
The Electric field will be  
  • E.F. = volume density * volume
  •        =  5.80 * 18.8
  •        =109.04
At 4.70 mm
Electric Field will be
E.F. = volume density* volume
         = 5.80* 9.40
          = 256.244
At 26mm
E.F. = volume density * volume
        = 5.80 * 244.4
        = 1417.52
 

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...