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# The electric potential decreasesfrom Vto-V along x axis in a coordinate system as we move from point (-x, 0) to (x, 0) then field at the origin will be1must be equal to v/x2.may be equal to v/x3.must be greater than v/x4.may be less than v/xPlease explain all the options

Arun Kumar IIT Delhi
7 years ago
Hi Ashu
$E=-dv/dx \\=>E_{avg}=-(-V-V)/2x=v/x$
here we could find only E average because we are using
$\Delta V \,instead \,of \,dV \,\\and\,\Delta x\,instead \,of \,dx$
So we can say i might be equal to v/x because there could be some other functions of V dependent of x.

Thanks & Regards
Arun Kumar
IIT Delhi