help@askiitians.com

1800-150-456-789

Electrostatics> The electric field at (30,30) cm due to a...

question mark

The electric field at (30,30) cm due to a charge of -8nC at the origin in N/C

Saher katchi , 7 Years ago

Grade 12

1 Answers

Eshan

Last Activity: 6 Years ago

Dear student,

Distance between origin and point (30,30)cm or (0.3,0.3)m is $d=sqrt{0.3^2+0.3^2}=0.3\sqrt{2}m$

Therefore, electric field at the point= $\dfrac{1}{4\pi\epsilon_0}\dfrac{q}{d^2}=9\times 10^9\times \dfrac{8\times 10^{-9}}{0.18}N=400N$ towards the origin.

LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

Full Live Access

Study Material

Live Doubts Solving

Daily Class Assignments

Electrostatics question based on earthing of spherical shell

electrostatics

0 Answer Available

Last Activity: 2 Years ago

an object has a charge of 2c and gains 10^19 electrons. the net chaarge on the object becomes??

electrostatics

1 Answer Available

Last Activity: 3 Years ago

A wire with a linear charge density lambda forms a quarter of a cjrclenof radius R and is placed asa shown in thefigure with its centre of curvature at the origin O the electric field at O will be

electrostatics

0 Answer Available

Last Activity: 3 Years ago

Find the value of q so that system remains in equilibrium.. figure attached below

electrostatics

0 Answer Available

Last Activity: 3 Years ago

Find the value of q so that system remains in equilibrium

electrostatics

0 Answer Available

Last Activity: 3 Years ago

View all Questions