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Grade: 12

                        

the dimensional formula of the permittivity of vacuum

the dimensional formula of the permittivity of vacuum

3 years ago

Answers : (2)

Saurabh Kumar
24 Points
							PEMITTIVITY= (CHARGE)^2 /(FORCE)*(DISTANCE)^2                       =[TA]^2 / [MLT^ -2] [L]^2                       =[TA]^2 / [ML^3T^ -2]                       =[M^ -1 L^ -3 T^2+2 A^2]                      = [M^ -1 l^ -3 T^4 A^2]
						
3 years ago
Anjali kumari
104 Points
							
It's dimension is M^-1L^-3T^4A^2. As permittivity=q1q2/4πFr^2. Sahi sell do aap devi sathi del zal zero aap so do LO
2 years ago
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