Question attached.. [ALTS-3 2013 Q37]
ANMOL SETH , 10 Years ago
Grade 12th pass
Electrostatics> Question attached.. [ALTS-3 2013 Q37]
1 Answers
Atal Tiwari
Last Activity: 10 Years ago
By symmetry net electic field along X-axis at the centre O is zero and electric field along Y-axis will be added up.
dEY=1/4pi-epsilon-naught x dq/r2sin@
but dq= ∂(rd@)=q/pi-r x (rd@) = q/pi d@
therefore, EY=2 x 1/4-pi-epsilon-naught ∫pi/20 (q/pi sin@ d@)/r2
=q/2-pi2-epsilon naught-r2.
Hence, the correct part is (a).
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