plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz solve question no 26
YASH AHUJA , 6 Years ago
Grade 11
Electrostatics> plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz...
2 Answers
Khimraj
Last Activity: 6 Years ago
SInce both charge of same sign so third charge q sholud placed in between of 4Q and 2Q. So electric force by one charge is canceled by another.
Let it has distance d from 4Q.
then for equilibrium
K(4Q)(q)/d2 = K(2Q)(q)/(x-d)2
taking root both side
So d = 0.59x.
Ayush Gupta
Last Activity: 6 Years ago
As the two charges are positive we need a negative charge to maintain it in equilibrium.There is a short trick for this question (both are like charged) let x from small positive charge then,X=√Q1/(√Q1+√Q2)*r After solving we getx=0.59
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