PLEASE ANSWER FAST !!!!! Two identical spheres A and B each having a charge of 6.5 × 10 -7 C are separated by a distance of 50 cm in air. A third uncharged sphere of same size is brought in contact with the first then brougth in contact with the second and afterwards removed from both. What is the new electrical force between the first two spheres .

Question

PLEASE ANSWER FAST !!!!! Two identical spheres A and B each having a charge of 6.5 × 10 -7 C are separated by a distance of 50 cm in air. A third uncharged sphere of same size is brought in contact with the first then brougth in contact with the second and afterwards removed from both. What is the new electrical force between the first two spheres .

Arun · Answer

Charge on sphere A, q A = Charge on sphere B, q B = 6.5 × 10 −7 C Distance between the spheres, r = 50 cm = 0.5 m Force of repulsion between the two spheres, F =k* qa *qb / r^2 Where, ∈0 = Free space permittivity 1/ 4* pi* epsilon=9x10 9 N m 2 C 2 ∴F = 9 * 10^9 * (6.5* 10^ –7)^2 / 0.25 =1.52X10 -2 N Therefore, the force between the two spheres is 1.52 × 10 −2 N.

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

1 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Electrostatics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship