Vikas TU
Last Activity: 7 Years ago
Give V a chance to be the potential contrast. Give V of 1 a chance to drop = kq/r.
In the event that the volume of n drops = n 4/3πr3
Volume of greater drop =4/3πR3
At that point from the question
Volume of n drops = Volume of greater drop
n 4/3πr3 =4/3πR3
(n1/3r) = R
As charge stays saved
As 1 drop has charge q so the n drops will have nq charge.
Work done(Potential distinction (V)) = knq/(n1/3r)
= n2/3 kq/r
= n2/3 V
