Grade 9AlgebraMay be it is an easy question but it`s answer is not striking me how I should start so please help yogesh 8 Years agoGrade 9
Khimraj8 Years agoPotential at centre of curvature will due to total charge on curvatureSo V = (1/4πϵo)(3Q)/R + (1/4πϵo)(-2Q)/R + (1/4πϵo)(Q)/R = (1/2πϵo)(Q)/R.So option A is correct.
Amit8 Years agoHi there. Please can you post the attachment again as I am not able to see it . It is missing.Regards.