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how to calculate electric force between two charges when a dielectric slab of variable amount is placed between the. Image attached.

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anuj

8 Years agoGrade 12

2 Answers

Nikhil

8 Years ago

Dear Anuj,

Let firstly that both charges are placed at distance ‘d’ without dielectric

So, force b/w them = q²/4πε₀d²

Now we shift them towards each other at distance t

Keeping for constant so now

F = q²_eff /4πε₀t²

^{It comes out q_eff} = q(1-t/d)

Nikhil

Approved Tutor Answer8 Years ago

Now simply put dielectric b/w 2 charges having charge ^q_eff = q(1-t/d) located at distance t

use formula q²_eff /4πε₀ε_rt²

ε_{r = simply 3k/4 as it is varing linearly}

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