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how to calculate electric force between two charges when a dielectric slab of variable amount is placed between the. Image attached.

anuj , 7 Years ago
Grade 12
anser 2 Answers
Nikhil

Last Activity: 7 Years ago

Dear Anuj,
Let firstly that both charges are placed at distance ‘d’ without dielectric
So, force b/w them = q2/4​πε0d2
Now we shift them towards each other at distance t
Keeping for constant so now 
F = q2eff /4​πε0t2
It comes out qeff = q(1-t/d)
 

Nikhil

Last Activity: 7 Years ago

Now simply put dielectric b/w 2 charges having charge  qeff =  q(1-t/d) located at distance t
use formula  q2eff /4​πε0εrt2
εr = simply 3k/4 as it is varing linearly 
 

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