0

Guest

Courses New

Good evening sir... Answer is 1 St option. Explain it.

Good evening sir...
Answer is 1 St option.
 Explain it.

Question Image
Grade:

1 Answers

Eshan
askIITians Faculty 2095 Points
4 years ago
Dear student,

To obtain an output voltage asV_{net}, number of capacitors to be arranged in series=n_s=\dfrac{V_{net}}{V}

But the capacitance of such a series combination would be\dfrac{C}{n_s}.

Therefore number of such branches of series to be arranged in parallel to obtain the capacitance=n_p=\dfrac{C_{net}}{C/n_s}=n_s\dfrac{C_{net}}{C}
Therefore total number of such capacitors required=n_Sn_p=n_s^2\dfrac{C_{net}}{C}=\dfrac{C_{net}}{C}\dfrac{V_{net}^2}{V^2}

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Electrostatics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More