help@askiitians.com

1800-150-456-789

Electrostatics> Good evening sir... Answer is 1 St option...

question mark

Good evening sir...
Answer is 1 St option.
Explain it.

raju nagula , 7 Years ago

Grade

1 Answers

Eshan

Last Activity: 7 Years ago

Dear student,

To obtain an output voltage as $V_{net}$ , number of capacitors to be arranged in series= $n_s=\dfrac{V_{net}}{V}$

But the capacitance of such a series combination would be $\dfrac{C}{n_s}$ .

Therefore number of such branches of series to be arranged in parallel to obtain the capacitance= $n_p=\dfrac{C_{net}}{C/n_s}=n_s\dfrac{C_{net}}{C}$
Therefore total number of such capacitors required= $n_Sn_p=n_s^2\dfrac{C_{net}}{C}=\dfrac{C_{net}}{C}\dfrac{V_{net}^2}{V^2}$

LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

Full Live Access

Study Material

Live Doubts Solving

Daily Class Assignments

Electrostatics question based on earthing of spherical shell

electrostatics

1 Answer Available

Last Activity: 2 Years ago

an object has a charge of 2c and gains 10^19 electrons. the net chaarge on the object becomes??

electrostatics

1 Answer Available

Last Activity: 3 Years ago

A wire with a linear charge density lambda forms a quarter of a cjrclenof radius R and is placed asa shown in thefigure with its centre of curvature at the origin O the electric field at O will be

electrostatics

1 Answer Available

Last Activity: 3 Years ago

Find the value of q so that system remains in equilibrium.. figure attached below

electrostatics

1 Answer Available

Last Activity: 3 Years ago

Need to find the time taken for the dipole to come back to eqm

electrostatics

1 Answer Available

Last Activity: 3 Years ago

View all Questions