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Grade: 12

                        

Force of attraction between plates of parallel plate capacitor derivaton

6 years ago

Answers : (2)

Nirmal Singh.
askIITians Faculty
44 Points
							
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Regards,
Nirmal SIngh
Askiitians Faculty
6 years ago
Kuntal Paul
42 Points
							If air is the medium between the plates of the parallel plate capacitor, then the electrical field at the position of the grounded plate will be E`=σ/2ε; and the electrical field at that place for the grounded plate itself will be E"=0, as for the grounded plate itself there will be equal but opposite amount of field produced. So net will be zero. Now, at the place of that grounded plate, net electrical field will be, E=E`+E"=σ/2ε. Again, the amount of negative charge on the inward surface of the plate is σA, where A is its area.Therefore, the attractive force between them will be, F=E(σA)Or, F=((σ^2)A/2ε)Or, F= q^2/2εA [as σ=q/A]
						
3 years ago
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