For a dipole, q= 2 × 10 -6 C and d = 4 cm. The external electric field if maximum torque experienced by this dipole is 10 -2 Nm, is

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Khimraj · Answer

maximum torque experienced by this dipole is given by qdE so 10 -2 = 2*10 -6 *4*10 -2 *E So E = 1.25*10 5 N/C. Hope it clears. If you like anser then please approve it.

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For a dipole, q= 2 × 10 -6 C and d = 4 cm. The external electric field if maximum torque experienced by this dipole is 10 -2 Nm, is

For a dipole, q= 2 × 10^-6 C and d = 4 cm. The external electric field if maximum torque experienced by this dipole is 10^-2 Nm, is

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For a dipole, q= 2 × 10 -6 C and d = 4 cm. The external electric field if maximum torque experienced by this dipole is 10 -2 Nm, is

For a dipole, q= 2 × 10-6 C and d = 4 cm. The external electric field if maximum torque experienced by this dipole is 10-2 Nm, is

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For a dipole, q= 2 × 10^-6 C and d = 4 cm. The external electric field if maximum torque experienced by this dipole is 10^-2 Nm, is