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Grade 12Electrostatics

Find the sign of charge q placed in middle of BC SO THAT CHARGE AT A IS IN EUILLIBRIUM

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Profile image of Narinder Kumar
5 Years agoGrade 12
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ApprovedApproved Tutor Answer1 Year ago

To determine the sign of the charge \( q \) placed in the middle of segment BC such that the charge at point A is in equilibrium, we need to analyze the forces acting on the charge at A due to the other charges present. Let's assume we have a configuration where charges are located at points A, B, and C along a straight line. For simplicity, let’s denote the charge at A as \( Q_A \), the charge at B as \( Q_B \), and the charge at C as \( Q_C \). The charge \( q \) is placed at the midpoint of BC.

Understanding Equilibrium Conditions

For the charge at A to be in equilibrium, the net force acting on it must be zero. This means that the attractive and repulsive forces from charges B and C, along with the force from charge \( q \), must balance each other out.

Analyzing Forces

Let’s break down the forces:

  • The force exerted on \( Q_A \) by \( Q_B \) is given by Coulomb's law: F_{AB} = k \frac{|Q_A Q_B|}{r_{AB}^2}, where \( r_{AB} \) is the distance between A and B.
  • The force exerted on \( Q_A \) by \( Q_C \) is: F_{AC} = k \frac{|Q_A Q_C|}{r_{AC}^2}, where \( r_{AC} \) is the distance between A and C.
  • The force exerted on \( Q_A \) by \( q \) is: F_{qA} = k \frac{|Q_A q|}{r_{qA}^2}, where \( r_{qA} \) is the distance from A to the midpoint of BC.

Determining the Sign of Charge q

Now, let’s consider the signs of the charges:

  • If \( Q_A \) is positive, then \( Q_B \) and \( Q_C \) must exert forces that either attract or repel \( Q_A \) depending on their signs.
  • If \( Q_B \) is positive and \( Q_C \) is negative, the force \( F_{AB} \) will repel \( Q_A \) while \( F_{AC} \) will attract it. In this case, \( q \) must be negative to attract \( Q_A \) back towards the center.
  • If both \( Q_B \) and \( Q_C \) are positive, \( q \) must be negative to provide an attractive force towards A, balancing the repulsive forces from B and C.

Example Scenario

Let’s say we have:

  • Charge at A: \( Q_A = +1 \, \text{C} \)
  • Charge at B: \( Q_B = +2 \, \text{C} \)
  • Charge at C: \( Q_C = -3 \, \text{C} \)

In this case, the repulsive force from \( Q_B \) will push \( Q_A \) away, while the attractive force from \( Q_C \) will pull it towards C. To achieve equilibrium, \( q \) must be negative, providing an additional attractive force towards itself, counteracting the repulsion from \( Q_B \).

Final Thoughts

In summary, the charge \( q \) placed in the middle of BC must have a sign opposite to that of the charge at A to ensure that the forces acting on A balance out, leading to equilibrium. The specific configuration of the other charges will dictate the exact nature of \( q \), but the principle remains consistent: opposite charges attract, and like charges repel.