Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Eight oil drops of same size are charged to a potential of 50 V each.These oil drops are merged into one single large drop. What will be the potential of the large drop?Sir explain it with answer.

Eight oil drops of same size are charged to a potential of 50 V each.These oil drops are merged into one single large drop.
What will be the potential of the large drop?Sir explain it with answer.

Grade:12th pass

3 Answers

Ravneet
104 Points
2 years ago
Volume of 8 drop of radius ‘r’ = Volume of big drop of radius ‘R’ 
       8 X  4/3pi(r3 )= 4/3pi(R3)
            R = 2r 
potental of small drop  = kq/r = 50
potential of big drop = kq/2r = 50/2 = 25V
Ravneet
104 Points
2 years ago
potential of bigger drop = k(8q)/2r = 4kq/r   Becouse R = 2r
and kq/r = 50 V 
so potential of bigger drop = 4 X 50  =  200 V
Chaitanya Prakhar Sharma
15 Points
2 years ago
Use 
Potential =(n^2/3) kq/R=(n^2/3)v
n=no of drops
v=voltage given
put n=8 and v=50
Let's check its working
According to our problem
Potential of big drop = (8^2/3)*50
                                      =  4*50
                                      =200
Welcome!!!
 
 
 
 
 
 
 
 
 
 
Thank you...

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free