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Grade: 12th pass

                        

Charge divide in two parts and place at same finite distance of much

Charge divide in two parts  and place at same finite distance of much 
 

one year ago

Answers : (2)

Arun
25768 Points
							
Dear Alok
 
Question is incomplete. Please fheck and rrpsotthis. You can also attach an image. I will be happy to help you.
one year ago
Vikas TU
14136 Points
							
Deat student 
Let the charges be q and (Q – q). Suppose, the distance between them is ‘x’.
The force between them is, F = kq(Q – q)/x2 = (k/x2)(qQ – q2)
The force is extremum when dF/dq = 0
So,
d[(k/x2)(qQ – q2)]/dq = 0
=> (k/x2)(Q – 2q) = 0
=> q = Q/2
Thus, the force will be maximum when the charge on each object is Q/2.
Good Luck 
one year ago
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