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# Can someone help with Q16 that`s in the attachment. Thank you.

Naren Ks
36 Points
5 years ago
the ans is 6 C
if u redraw the circuit u will see that all the capacitors are in parallel
by using the formula c(EQUIVALENT OF PARALLEL COMBINATION)=C1+C2+...
Umakant biswal
5359 Points
5 years ago
@ ashmeet
as in this circuit there are no battery or cell combination .
so, this ques becomes easy.
just redraw the circuit where 3 of them are in parallely connected .
then applying the following formula
1/C (EQUIVALENT ) = 1/C1 +1C2 +1/C3 + ….....................1/C6
AND option no A will turns out to be the correct answer .
HOPE U CAN SOLVE IT
IF ANSWER IS COMING DIFFRENT ,THEN LET ME  KNOW .
I WILL SOLVE IT FULLY
ALL THE BEST ..
Archishman khasnovis
15 Points
5 years ago
I think the answer will be option d because the first 3 capacitors are undoubtedly parallel but the next 2 capacitors are parallel and finally the first 3 next 2 and the last one are in series
Raman Mishra
67 Points
5 years ago
The correct answer for this question is 3C/4. For solving these types of questions, mark the capacitor plates having same voltages and then simplify the circuit diagram by connecting the same voltage terminals together. Following this technique we can see that the first three capacitors are in parallel, the next two capacitors are short-circuited(if we assume a voltage source to be connected across P and Q) and the last capacitor is in series. Thus the simplified circuit will be: first three capacitors in parallel and the last capacitor in series with the parallel combination.
$\therefore$ Ceq = C+C+C in series with C
=> Ceq = 3C/4