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An electric field is given E=2xi-3y^2j N/C. Find the change in potential from the position r=(i-2j) m to r=(2i+j+3k) m

An electric field is given E=2xi-3y^2j N/C. Find the change in potential from the position r=(i-2j) m to r=(2i+j+3k) m

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Grade:12

1 Answers

Khimraj
3007 Points
5 years ago
dV = – \intE.dr
V = -\int_{1}^{2}2xdx -\int_{-2}^{1}(-3y)dy -\int_{0}^{3}0dz
So \DeltaV = 6V
Hope it clears.

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