A wire AB of length L has a linear charge density (Lambda) is equals to Kx where X is measured from the end A of the wire . The wire is enclosed by gaussian Hollow surface. find the expression for the electric flux through this Surface
Nihaal , 6 Years ago
Grade 12
1 Answers
Chandan
Last Activity: 6 Years ago
q=lambda*A
=kl2\2
therefore exp=kl2/eepsilon
hope it helps please approve if it does
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