Question icon
Grade 12Electrostatics

A wire AB of length L has a linear charge density (Lambda) is equals to Kx where X is measured from the end A of the wire . The wire is enclosed by gaussian Hollow surface. find the expression for the electric flux through this Surface

Profile image of Nihaal
8 Years agoGrade 12
Answers icon

1 Answer

Profile image of Chandan
8 Years ago
q=\intlambda*A
 
=kl2\2
therefore exp=kl2/eepsilon
hope it helps please approve if it does