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A thin wire ring of radius r has an electric charge​ q. The increment in the tension in the wire if a point q౦ is placed centre of the Ring is?

Meghana Bhat , 8 Years ago
Grade 12
anser 1 Answers
Vikas TU

Last Activity: 7 Years ago

Surface area of the  ring will be  = pi R^2
Hence the tension produced = Q * surface area
                                                     = Q *pi* R^2
Therefore, the increment in the tension in the wire if a point q౦ is placed centre of the Ring is Q *pi* R^2

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