A thin conducting ring is ruptured when it is given a charge q. Consider another thin conducting ring, radius of which is n times and tensile strength is k times of the former ring. How much maximum charge can this second ring be given without rupturing?

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Arun · Answer

Dear student I am getting my answer as maximum charge = q * n * sqrt(k) hope it helps Regards Arun (askIITians forum expert)

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A thin conducting ring is ruptured when it is given a charge q. Consider another thin conducting ring, radius of which is n times and tensile strength is k times of the former ring. How much maximum charge can this second ring be given without rupturing?

A thin conducting ring is ruptured when it is given a charge q. Consider another thin conducting ring, radius of which is n times and tensile strength is k times of the former ring. How much maximum charge can this second ring be given without rupturing?

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A thin conducting ring is ruptured when it is given a charge q. Consider another thin conducting ring, radius of which is n times and tensile strength is k times of the former ring. How much maximum charge can this second ring be given without rupturing?

A thin conducting ring is ruptured when it is given a charge q. Consider another thin conducting ring, radius of which is n times and tensile strength is k times of the former ring. How much maximum charge can this second ring be given without rupturing?

1 Answers

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Other Related Questions on Electrostatics

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