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A thin conducting ring is ruptured when it is given a charge q. Consider another thin conducting ring, radius of which is n times and tensile strength is k times of the former ring. How much maximum charge can this second ring be given without rupturing?

A thin conducting ring is ruptured when it is given a charge q. Consider another thin conducting ring, radius of which is n times and tensile strength is k times of the former ring. How much maximum charge can this second ring be given without rupturing?

Grade:12

1 Answers

Arun
25758 Points
3 years ago
Dear student
 
I am getting my answer as 
maximum charge = q * n * sqrt(k)
 
hope it helps
 
Regards
Arun (askIITians forum expert)

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