Electric Current

a small particle carrying a negative charge of 1.6*10^-19 c is suspended in equilibrium between the horizontal metal plates 5 cms apart, having a potential difference of 3000v across them. find the mass of the particle?

Kumar Adarsh

8 Years agoGrade

3 Answers

Arun

8 Years ago

Dear student

E = dV/dr = 3000/5 * 10^-2 = 6 * 104 volt /m

Now qE = mg

m = q E /g = 1.6 * 10^-19* 6 * 10^4 /9.8

= 9.8 * 10^-16 kg

Saurav

8 Years ago

JUST APPLY YOUR MIND OR THE FORMULAS BELOW .IT’S YOUR CHOICE

IF YOU APLLY MIND YOU WON’T NEED TO REMEMBER FORMULAS:

E = dV/dr

qE = mg (THIS IS OBVIOUSLY FOR ABOVE GIVEN QUESTION AND NOT GENERAL)

Gitanjali Rout

8 Years ago

= dV/dr = 3000/5 * 10^-2 = 6 * 104 volt /m

Now qE = mg

m = q E /g = 1.6 * 10^-19* 6 * 10^4 /9.8

= 9.8 * 10^-16 kg

E = dV/dr

qE = mg (THIS IS OBVIOUSLY FOR ABOVE GIVEN QUESTION AND NOT GENERAL).

E = dV/dr = 3000/5 * 10^-2 = 6 * 104 volt /m

Now qE = mg

m = q E /g = 1.6 * 10^-19* 6 * 10^4 /9.8

= 9.8 * 10^-16 kg.

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a small particle carrying a negative charge of 1.6*10^-19 c is suspended in equilibrium between the horizontal metal plates 5 cms apart, having a potential difference of 3000v across them. find the mass of the particle?

Kumar Adarsh

3 Answers

Arun

Saurav

Gitanjali Rout

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