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Grade: 12

                        

a rod of length l has a charge q distributed uniformly along its length.it is bent in shape of a semicircle.find magnitude of electric field at centre of curvature of semicircle.

5 years ago

Answers : (2)

IVIN ZACHARIA THOMAS
38 Points
							
Consider a gaussian surface of radius R enclosing the given sphere of radius r(L/2*3.14) 
Then electric field inside the sphere=Q*r*K/R*R
at the centre, r=0
therefore elctric field at the centre is 0
so electric field at the centre of curvature of semicircle is 0
5 years ago
Akshita Goyal
17 Points
							
no correct answer is q/2Eol^2.
5 years ago
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