a rod of length l has a charge q distributed uniformly along its length.it is bent in shape of a semicircle.find magnitude of electric field at centre of curvature of semicircle.

Question

IVIN ZACHARIA THOMAS · Answer

Consider a gaussian surface of radius R enclosing the given sphere of radius r(L/2*3.14) Then electric field inside the sphere=Q*r*K/R*R at the centre, r=0 therefore elctric field at the centre is 0 so electric field at the centre of curvature of semicircle is 0

Akshita Goyal · Answer

no correct answer is q/2Eol^2.

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a rod of length l has a charge q distributed uniformly along its length.it is bent in shape of a semicircle.find magnitude of electric field at centre of curvature of semicircle.

a rod of length l has a charge q distributed uniformly along its length.it is bent in shape of a semicircle.find magnitude of electric field at centre of curvature of semicircle.

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