Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A ring of radius r carries a charge Q unifirmly distributed over its length a charge q is placed at its center will experiences a force
The force experienced by charge q placed at centre of ring will be zero.As electric field at centre of ring is always zero.Hope it clears.
let a particle be at point P at a distance x from centre of ring.Then electric field at point P if given by the formula kQx/(x^2+r^2)^3/2as here x =0 => E = 0 => F = qE =0
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -