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A ring of radius r carries a charge Q unifirmly distributed over its length a charge q is placed at its center will experiences a force
The force experienced by charge q placed at centre of ring will be zero.As electric field at centre of ring is always zero.Hope it clears.
let a particle be at point P at a distance x from centre of ring.Then electric field at point P if given by the formula kQx/(x^2+r^2)^3/2as here x =0 => E = 0 => F = qE =0
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