A ring of radius r carries a charge Q unifirmly distributed over its length a charge q is placed at its center will experiences a force

Question

Khimraj · Answer

The force experienced by charge q placed at centre of ring will be zero. As electric field at centre of ring is always zero. Hope it clears.

Shivangi Baral · Answer

let a particle be at point P at a distance x from centre of ring. Then electric field at point P if given by the formula kQx/(x^2+r^2)^3/2 as here x =0 => E = 0 => F = qE =0

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A ring of radius r carries a charge Q unifirmly distributed over its length a charge q is placed at its center will experiences a force

A ring of radius r carries a charge Q unifirmly distributed over its length a charge q is placed at its center will experiences a force

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