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`        A ring of radius 6 cm is given a charge 10 MC. how much work will be done in transporting a charge of 6 MC from its centre to a point 8 cm along its axis ? `
one year ago

Vinmuhilan
34 Points
```							Workdone =6MC(V at 8cm - V at centre)Pot. V due to a charged ring at any points On the axis = kq/(R^2+X^2)^0.5Pot at centre = kq/R [ Bcoz at centre X =0]Here X= 8cm ,q=10MC , R=6cm.
```
one year ago
Veeresh
13 Points
```							W=-q(Vfinal - V initial)W=q(Kq/Rinitial-Kq/Rfinal)W=140×10^-9{K(10×10^-6)/6×10^-2}-{K(10×10^-6)/8×10^-2
```
3 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions