A point charge of 5 C is placed at point P as shown. A unit positive charge is taken from A to B along the circular path shown. Then the net work done by electostatic forces is (O is the centre of the circular path) (where k=9×10^9 N m^2 /C^2)Plzz explain - +400k
- +4k
- -400k
- -4k
A point charge of 5 C is placed at point P as shown. A unit positive charge is taken from A to B along the circular path shown. Then the net work done by electostatic forces is (O is the centre of the circular path) (where k=9×10^9 N m^2 /C^2)
Plzz explain
- +400k
- +4k
- -400k
- -4k











