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A particle of charge Q and mass m is released from origin at t=0 sec(as shown in the fig.) a)what will be the position of particle and direction at t=1 sec b)what will be the magnitude and direction of electric field?
3 years ago

Answers : (1)

Abhishek Kumar
askIITians Faculty
253 Points
							Find out the electric field, hence the force and hence the acceleration. Then apply kinematics equations.
For electric field,
E = -dV/dr
These are equipotential surfaces shown. Electric field is perpendicular to the lines shown. Finf the magnitude = 10/(Perpendicular distance between the two lines)
Acceleration will have the same direction as of the electric field.
3 years ago
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