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A particle has apotential v=a/r^2 what is its corresponding force

Ezra , 6 Years ago
Grade 12
anser 2 Answers
Eshan

Last Activity: 6 Years ago

For a potential following the variationV=\dfrac{a}{r^2},

Electric field is given asE=-\dfrac{dV}{dr}=\dfrac{2a}{r^3}
Hence the force acting on the charge isF=qE=\dfrac{2qa}{r^3}

Khimraj

Last Activity: 6 Years ago

Potential is given by V = a/r2
Electric field E = -dV/dr = 2a/r3
And force will be given by F = qE = 2aq/r3.
Hope it clears.

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