Mechanics
A man throws a ball to maximum horizon talk distance of 80meters. Calcurate the maximum height reached
A man throws a ball to maximum horizon talk distance of 80meters. Calcurate the maximum height reached
2 Answers
Saurabh Koranglekar
Vikas TU
Dear student
Max range is for angle 45
80 = u^2 Sin^2(x)/g
Solve for u , you will get.
u = 40
max height=u^2 Sin^2(x)/2g
h=80/2m=40m
80 = u^2 Sin^2(x)/g
Solve for u , you will get.
u = 40
max height=u^2 Sin^2(x)/2g
h=80/2m=40m
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