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a dielectric is placed in between the two parallel plates of a capacitor as show . the dielectric constant of the dielectric beingK. if the inital capacity is C then the new capacity will be

a dielectric is placed in between the two parallel plates of a capacitor as show . the dielectric constant of the dielectric beingK. if the inital capacity is C then the new capacity will be

Grade:12

1 Answers

Jashandeep
20 Points
4 years ago
New capacitance=K × CExplanation-Let initial capacitance be CA is area between two platesAnd d is distance between themTherefore, C=(εA )÷dAfter placin dielectric between the platesLet capacitance be C1 Therefore,C1 =( KεA)÷dDividing C1 by C , what we get is the answer of your question i.e C1= K×C.

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