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# A conic surface is placed in a uniform electric field E as shown in figure such that the field is perpendicular to the surface AB the base of the cone is of radius R and the height is h the angle of cone is theta. Find the magnitude of the flux that enters the cone`s surface from the left side . Do not count the count the outgoing flux. (Theta

Khimraj
3007 Points
3 years ago
The electric flux through surface AB will be equal to electric flux through cross section of half cone.
flux = Eeff*Area = (Ecos$\Theta$)*( ½*2R*h) = ERhcos$\Theta$.