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Grade: 11
        
A conducting sphere of radius R carrying charge Q is connected to an uncharged conducting sphere of radius 2R .The charge that flows between them is
7 months ago

Answers : (2)

Arun
23049 Points
							
We know that charge will flow between them till the potential becomes same on both spheres.
Let us assume that a charge x flows between them
charge on larger sphere will be x and charge on smaller sphere will be Q - x
Potential on smaller sphere = k (Q - x) / R
Potential on larger sphere = k x /2R
Equating the potentials
k (Q - x) / R = k x /2R
Q - x = x/2
3x/2 = Q
x = 2Q/3
Thus a charge of 2Q/3 will flow between them
-
However if you consider them concentric spheres, such that smaller sphere lies inside the larger sphere. Then potential on inner sphere will be always greater. If you connect them, the whole charge Q will be emptied from the inner sphere
 
7 months ago
Khimraj
3008 Points
							
potential becomes same on both spheres. So
k (Q - x) / R = k x /2R
Q - x = x/2
3x/2 = Q
x = 2Q/3
so charge flow = Q -x = Q/3
Hope it clears...........................................
 
6 months ago
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