A charged particle of mass 0.003g is held stationary in space by placing it in a downward direction of electric field of 6x10^4 N/C. Then, the magnitude of charge is?

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Ankit Kumar · Answer

m=0.003g=3×10 -6 E=6×10 4 N/C mg=F (F=qE) mg=qE 3×10 -6 ×10=q×6×10 4 By dividing the value of E by Left Hand Side you will get the answer written below q=5×10 -10 C

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A charged particle of mass 0.003g is held stationary in space by placing it in a downward direction of electric field of 6x10^4 N/C. Then, the magnitude of charge is?

A charged particle of mass 0.003g is held stationary in space by placing it in a downward direction of electric field of 6x10^4 N/C. Then, the magnitude of charge is?

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A charged particle of mass 0.003g is held stationary in space by placing it in a downward direction of electric field of 6x10^4 N/C. Then, the magnitude of charge is?

A charged particle of mass 0.003g is held stationary in space by placing it in a downward direction of electric field of 6x10^4 N/C. Then, the magnitude of charge is?

1 Answers

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Other Related Questions on Electrostatics

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