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A charge 3q experience a force 3000n is placed in a uniform electric field the potential diffrence btw points separated by distance 1 cm is ??

Aditya Garg , 7 Years ago
Grade 10
anser 1 Answers
Vikas TU

Last Activity: 7 Years ago

As we all know that,
Potential Difference = Force * charge /distance
Putting the values after we get,
                                  = 3000 * 3q/100
                                     = 900q.

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