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64 identical drops each of radius 1 cm and charged to the same potential 100 V and combined to form a single drop .the charge on the new drop will be about

64 identical drops each of radius 1 cm and charged to the same potential 100 V and combined to form a single drop .the charge on the new drop will be about

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Grade:12

2 Answers

Eshan
askIITians Faculty 2095 Points
5 years ago
Dear student,

Since the total charge on the drops will be conserved, the charge on the 64 drops will be equal to that on the single drop.

Potential of each small drop==\dfrac{kq}{r}=100
\implies q=\dfrac{1}{9}\times 10^{-9}C

Hence total charge on 64 drops=64q=\dfrac{64}{9}\times 10^{-9}C\approx 7nC
Khimraj
3007 Points
5 years ago
potential of one ball is 100V
So
Kq/r = 100
9*109*q/0.01 = 100
Then q = (1/9)*10-9
So charge of 64 ball = (64/9)*10-9C = 7nC
Hope it clears.

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