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2 point charges in air are at a distance of 20 cm.from each other interact with a certain force.at what distance from each other should these charges be placed  in oil of permittivity  5 to obtain the same force of interaction?

mahshida hamid , 8 Years ago
Grade 12
anser 1 Answers
aniket

Last Activity: 8 Years ago

first find out the force due to the charge in air 
then you know that ∂=5
you get r =0.089
  • use F= (1/4pi∂∂not) q1q2/r2 where r is unknown

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